Question

Корень из 3 +2cosx=0

Answer 1

√3+2cosx=0
2cosx=-√3
cosx=-√3/2
x=+-(π-arccos√3/2)+2πn, n∈Z
x=+-(π-π/6)+2πn, n∈Z
x=+-5π/6+2πn, n∈Z

Answer 2

To solve the equation √3 + 2cos(x) = 0, we need to isolate the cosine term on one side and then solve for x. Here's the step-by-step process:

1. Move √3 to the other side of the equation: 2cos(x) = -√3

2. Divide both sides by 2 to isolate cos(x): cos(x) = -√3/2

Now, we need to find the values of x that satisfy this equation. In which interval are you interested in finding the solutions? The solutions can be found in multiple intervals due to the periodic nature of the cosine function. Common intervals to consider are [0, 2π] or [-π, π]. Let me know which interval you are interested in, and I can help you find the solutions within that range.