Question

Tg(a+b)=8, tgb=-3 , то tga=?

Answer 1

$tg(a+b) = \frac{tg(a) + tg(b)}{1-tg(a)*tg(b)}$

$8 = \frac{tg(a)-3}{1+3*tg(a)}$

8+ 24*tg(a) = tg(a)-3 23*tg(a) = -11

tg(a) = -11/23

Answer 2

To find the value of tga, we can use the given information:

1. Tg(a + b) = 8
2. Tg(b) = -3

We know that the tangent of the sum of two angles (a + b) can be expressed as follows:

Tg(a + b) = (Tg(a) + Tg(b)) / (1 - Tg(a) * Tg(b))

Now, we can plug in the known values:

8 = (Tg(a) - 3) / (1 + 3 * Tg(a))

Let's solve for Tg(a):

8(1 + 3 * Tg(a)) = Tg(a) - 3

8 + 24 * Tg(a) = Tg(a) - 3

24 * Tg(a) - Tg(a) = -3 - 8

23 * Tg(a) = -11

Tg(a) = -11 / 23

So the value of Tg(a) is approximately -0.478.