Question

6(2х+3)-7(3х-4)=14х4(3х+7)-6(2х+5)=5х-16(х-4)+2,3=3(2х-7)-8

Answer 1

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Answer 2

To solve the given equation, we need to find the value of 'x'. Let's break down the equation step by step and solve it:

1. 6(2x + 3) - 7(3x - 4) = 14x + 4(3x + 7) - 6(2x + 5) = 5x - 16(x - 4) + 2.3 = 3(2x - 7) - 8

Step 1: Distribute the terms within parentheses.

6 * 2x + 6 * 3 - 7 * 3x + 7 * 4 = 14x + 4 * 3x + 4 * 7 - 6 * 2x - 6 * 5 = 5x - 16 * x + 16 - 2.3 = 3 * 2x - 3 * 7 - 8

Step 2: Simplify each side.

12x + 18 - 21x + 28 = 14x + 12x + 28 - 12x - 30 = 5x - 16x + 16 - 2.3 = 6x - 21 - 8

Step 3: Combine like terms.

(12x - 21x) + (18 + 28) = 14x + 12x - 12x + (28 - 30) = 5x - 16x + 16 - 2.3 = 6x - 29

Step 4: Continue simplification.

-9x + 46 = 14x - 2 = 6x - 29

Step 5: Move all x terms to one side and constants to the other side.

-9x - 14x = -2 - 46 = 6x - 29

Step 6: Combine like terms again.

-23x = -48 = 6x - 29

Step 7: Isolate 'x' by dividing by the coefficient of 'x.'

x = (-48) / (-23) = 48 / 23 ≈ 2.08696 (rounded to five decimal places)

So, the value of 'x' is approximately 2.087.