Question

A+b-10ab=2(3-b)-3b(a-2)-5(ab+a+b) тождественно ли оно???

Answer 1

A+b-10ab = 2(3-b)-3b(a-2)-5(ab+a+b)
возьмём вторую часть и попробуем ее преобразовать
2(3-b)-3b(a-2)-5(ab+a+b) = 6-2b-3ab+6b-5ab-5a-5b = 6-7b-8ab+b-5a = 6-5a-6b-8ab
ответ: нет

Answer 2

To check whether the given equation is an identity (true for all values of variables) or not, we need to determine if it holds true for all values of 'a' and 'b'. To do this, we can simplify both sides of the equation and see if they are equal.

Given equation: A + B - 10AB = 2(3 - B) - 3B(A - 2) - 5(AB + A + B)

Let's simplify both sides step by step:

Step 1: Expand the right side of the equation 2(3 - B) - 3B(A - 2) - 5(AB + A + B) = 6 - 2B - 3AB + 6B - 10AB - 5A - 5B

Step 2: Combine like terms on the right side = -5A - 5B - 13AB + 6

Now, the equation becomes: A + B - 10AB = -5A - 5B - 13AB + 6

Step 3: Group like terms on both sides: A - 5A + B - 5B - 10AB + 13AB = 6

Step 4: Simplify further: -4A - 4B + 3AB = 6

Step 5: Divide both sides by 1 to make it look like a standard form: (3AB - 4A - 4B) = 6

Now, we have simplified the equation to the form (3AB - 4A - 4B) = 6.

This equation is not an identity because it is not true for all values of 'a' and 'b'. An identity would be an equation that holds true for all possible values of the variables, but in this case, the equation depends on specific values of 'a' and 'b' for it to be true.