Question

(0,2t+4y)(0,04t2−0,8ty+16y2)

Answer 1

0,008t^3-1,6t^2y+3,2y^2t+0,16yt^2-3,2t^2y+64y^3=0,08t^3+0,16yt^2+4,8y^2t+64y^3
Вроде правильно

Answer 2

To multiply the two given expressions, we'll use the distributive property. The expression (0,2t+4y) means that the first term is 0 and the second term is 2t + 4y. The expression (0,04t^2 - 0,8ty + 16y^2) means that the first term is 0 and the second term is 0.04t^2 - 0.8ty + 16y^2.

Now, let's perform the multiplication:

(0,2t+4y)(0,04t^2−0,8ty+16y^2)

= 0 * (0.04t^2−0.8ty+16y^2) + (2t+4y) * (0.04t^2−0.8ty+16y^2)

= 0 + 2t * (0.04t^2−0.8ty+16y^2) + 4y * (0.04t^2−0.8ty+16y^2)

= 0 + 0.08t^3 - 1.6t^2y + 32ty^2 + 0 + 0.16ty^2 - 3.2y^3 + 0

Now, let's combine like terms:

= 0.08t^3 - 1.6t^2y + 32ty^2 + 0.16ty^2 - 3.2y^3

Finally, the result of the multiplication is:

0.08t^3 - 1.6t^2y + 32ty^2 + 0.16ty^2 - 3.2y^3