Question

(y+5)(y+2)-(y+3)(y+4) при y=0,071

Answer 1

(y+5)(y+2)-(y+3)(y+4)

(y²+2y+5y+10)-(y²+4y+3y+12)

y²+7y+10-y²-7y-12

(0,071)²-(0,071)²+7*0,071-7*0,071+10-12

+10-12

-2

Answer 2

(у+5)(у+2)-(у+3)(у+4)=у^2+2у+5у+10-(у^2+4у+3у+12)=у^2+2у+5у+10у-у^2-4у-3у-12=7у+10-7у-12=-2

Answer 3

To find the value of the expression $(y+5)(y+2)-(y+3)(y+4)$ when $y=0.071$, simply substitute the value of $y$ into the expression and perform the calculations:

$(0.071 + 5)(0.071 + 2) - (0.071 + 3)(0.071 + 4)$

Now, let's compute the result step by step:

Step 1: Calculate the values inside the parentheses. $0.071 + 5 = 5.071$ $0.071 + 2 = 2.071$ $0.071 + 3 = 3.071$ $0.071 + 4 = 4.071$

Step 2: Perform the multiplication. $5.071 \times 2.071 = 10.485241$ $3.071 \times 4.071 = 12.506041$

Step 3: Perform the subtraction. $10.485241 - 12.506041 = -2.0208$

So, when $y=0.071$, the value of the expression $(y+5)(y+2)-(y+3)(y+4)$ is approximately $-2.0208$.