Question

Решите уравнение x^2=-4x+32

Answer 1

x²=-4x+32

х²+4х-32=0

Д= 4²-4×1×(-32) = 16 + 128 = 144

х1 = -4 + 12 / 2 = 4

х2 = -4-12 / 2 =-8

Answer 2

${x}^{2} + 4x - 32 = 0 \\ d = 16 + 128 = 144 \\ x1 = \frac{ - 4 - 12}{2} = - 8 \\ x2 = \frac{ - 4 + 12}{2} = 4$

Ответ:-8,4.

Answer 3

To solve the quadratic equation x^2 = -4x + 32, we need to bring all terms to one side of the equation and set it to zero. Then, we can use factoring or the quadratic formula to find the solutions for x.

Step 1: Rewrite the equation in standard form: x^2 + 4x - 32 = 0

Step 2: Factor the quadratic expression, if possible: (x + 8)(x - 4) = 0

Step 3: Set each factor to zero and solve for x: Setting x + 8 = 0: x = -8

Setting x - 4 = 0: x = 4

The solutions to the equation are x = -8 and x = 4.