Question

Х(х+2)(х-2)-(х-3)(х²+3х+9) При х=0,25.

Answer 1

x(x²-4)-(x³-27)= x³-4x-x³+27= 27-4x= 27-4*0,25= 27-1= 26

Answer 2

х(х+2)(х-2)-(х-3)(х²+3х+9)=x(х²-4)-(х-3)(х²+3х+9)=$x^{3}$-4x-($x^{3}$+3х²+9x-3х²-9x+27)=$x^{3}$-4x-$x^{3}$+27=-4x+27

-4*0,25+27=-1+27=26

Answer 3

To evaluate the expression when x = 0.25, simply substitute the value of x into the expression and perform the calculations step by step:

1. Start with the given expression: Х(х+2)(х-2)-(х-3)(х²+3х+9)

2. Substitute x = 0.25 into the expression:

0.25(0.25 + 2)(0.25 - 2) - (0.25 - 3)(0.25² + 3(0.25) + 9)

3. Perform the calculations within parentheses:

0.25(2.25)(-1.75) - (-2.75)(0.0625 + 0.75 + 9)

4. Continue with the multiplication and addition:

0.25 * 2.25 * -1.75 - (-2.75) * (0.8125)

5. Calculate the values:

-0.984375 - (-2.23828125)

6. Finally, subtract the two values:

-0.984375 + 2.23828125 ≈ 1.25390625

So, when x = 0.25, the value of the expression Х(х+2)(х-2)-(х-3)(х²+3х+9) is approximately 1.25390625.