Question

Дана функция у=х^+х-4 найдите значения функций у(-4). У(2)

Answer 1

х^2+х-4=-4

х^2+х=0

х(х+1)=0

х1=0 или х2=-1

у (-4)=0;-1.

х^2+х-4=2

х^2+х-6=0

D=1-4×(-6)=25

x1=(-1+5)/2=2

x2=(-1-5)/2=-3

y (2)=-3;2.

Answer 2

To find the values of the function y = x^2 + x - 4 for specific values of x, simply substitute those values into the function.

1. For x = -4: y(-4) = (-4)^2 + (-4) - 4 y(-4) = 16 - 4 - 4 y(-4) = 8

2. For x = 2: y(2) = (2)^2 + (2) - 4 y(2) = 4 + 2 - 4 y(2) = 2

So, the values of the function y at x = -4 and x = 2 are 8 and 2, respectively.