Question

2x=11-2y 6y=22-4x способом постановки​

Answer 1

2x=11-2у,

6y=22-4x,

из 1 ур-ия:

х = (11-2у)/2,

подставляем во 2 ур-ие:

6у = 22 - 4*(11-2у)/2,

6у = 22 - 2*(11-2у),

6у = 22 - 22+4у,

6у - 4у = 22 - 22,

у = 0,

х = (11 - 2*0)/2 = 5,5

Answer 2

To solve the system of equations:

1. 2x = 11 - 2y
2. 6y = 22 - 4x

We can use the method of substitution or elimination. Let's use the substitution method:

Step 1: Solve one of the equations for one variable in terms of the other variable. Let's start with equation (1):

2x = 11 - 2y

To isolate x, divide both sides by 2:

x = (11 - 2y) / 2

Step 2: Now, substitute the expression we found for x in terms of y into the other equation (2):

6y = 22 - 4x

Replace x with (11 - 2y) / 2:

6y = 22 - 4((11 - 2y) / 2)

Step 3: Simplify the equation and solve for y:

6y = 22 - 2(11 - 2y)

Distribute the 2 on the right side:

6y = 22 - 22 + 4y

Combine like terms:

6y - 4y = 0

2y = 0

y = 0

Step 4: Now that we have the value of y, substitute it back into one of the original equations to find the value of x. Let's use equation (1):

2x = 11 - 2y

Substitute y = 0:

2x = 11 - 2(0)

2x = 11

Now, isolate x:

x = 11 / 2

x = 5.5

So the solution to the system of equations is x = 5.5 and y = 0.