Question

(B^4+2b^2)-b^2(b-1)(b+1)+2b(3-2b^2)

Answer 1

вот так решается если надо упростить.

Answer 2

Let's simplify the expression step-by-step:

1. B^4 + 2b^2 There is no simplification possible for this term, so we keep it as it is.

2. -b^2(b - 1)(b + 1) Expand the expression inside the brackets: = -b^2(b^2 + b - b - 1) = -b^2(b^2 - 1)

3. +2b(3 - 2b^2) Distribute the 2b: = 6b - 4b^3

Now, putting it all together:

(B^4 + 2b^2) - b^2(b - 1)(b + 1) + 2b(3 - 2b^2)

= B^4 + 2b^2 - b^2(b^2 - 1) + 6b - 4b^3

Now let's simplify further:

= B^4 + 2b^2 - b^4 + b^2 + 6b - 4b^3

Combine like terms:

= B^4 - b^4 + 3b^2 + 6b - 4b^3

The final simplified expression is:

B^4 - b^4 + 3b^2 + 6b - 4b^3