Question

A²-49=x²-0,81=256-a⁴=a³+125=64-b³=​

Answer 1

1. a²-49=(a-7)(a+7)
2. x²-0,81=(x-0,9)(x+0,9)
3. 256-a⁴=(16-a²)(16+a²)
4. a³+125=(a+5)(a²-5a+25)
5. 64-b³=(4-b)(16+4b+b²

Answer 2

Ответ:

a²-49 = (a - 7)(a + 7)

x²-0,81 = (x - 0,9)(x + 0,9)

256-a⁴ = (16 - a²)(16 + a²)

a³+125 = (a + 5)(a² - 5a + 25)

64 - b³ = ​(4 - b)(16 + 4b + b²)

Answer 3

Let's solve each equation step by step:

1. A² - 49 = x² - 0.81: To solve for A and x, we need more information, as we have two variables and only one equation. If you have any additional information or constraints, please provide them so that we can proceed with a unique solution.

2. 256 - a⁴ = a³ + 125: To solve for 'a,' we can rearrange the equation: a⁴ + a³ - 256 - 125 = 0 a⁴ + a³ - 381 = 0

Unfortunately, solving this quartic equation is quite complex, and the solutions involve using numerical methods. Without additional constraints or information, it's challenging to obtain a specific value for 'a.'

3. 64 - b³ = 0: To solve for 'b,' we can rearrange the equation: b³ = 64 Taking the cube root of both sides: b = ∛64 b = 4

So, the solution for the equation involving 'b' is b = 4.

If you have any other equations or additional information, please provide them so that I can assist you further.