Question

(^3√9+^3√6+^3√4)(^3√3-^3√2)

Answer 1

Ответ:

1

Объяснение:

$(\sqrt[3]{9}+\sqrt[3]{6}+\sqrt[3]{4})( \sqrt[3]{3}-\sqrt[3]{2})=\\\\=((\sqrt[3]{3})^2+\sqrt[3]{3}*\sqrt[3]{2}+(\sqrt[3]{2})^2)(\sqrt[3]{3}-\sqrt[3]{2})=\\\\=(\sqrt[3]{3})^3-(\sqrt[3]{2})^3=3-2=1$

Использована формула разности кубов

(a²+ab+b²)(a-b) =a³-b³

Answer 2

To simplify the given expression, let's break it down step by step:

First, let's simplify the individual cube roots:

∛9 = 2 ∛6 ≈ 1.817 ∛4 = 1.587 ∛3 ≈ 1.442 ∛2 ≈ 1.26

Now we can substitute these values into the expression:

(2 + 1.817 + 1.587)(1.442 - 1.26)

Performing the addition and subtraction:

(5.404)(0.182)

Finally, multiplying the two values together:

≈ 0.983