Question

N- наименьшее натуральное число, сумма которого равна 2020. n-? . 2n-?​

Answer 1

Ответ: 224 раза 9 и 4 : 99999....94, 2n равен 1, 223 раза 9 и 88 : 1999......988

Объяснение: для того чтобы число было наименьшим возможным, нужно чтобы его цифры были максимально большими. поэтому 2020:9=224, 224*9=2016, т.е нужно ещё 4. 2n=9999.......94*2=19999.....988

Answer 2

To find the smallest natural number N whose sum is equal to 2020, we can start with the smallest natural number 1 and keep adding consecutive natural numbers until we reach a sum of 2020.

Let's calculate:

1 + 2 + 3 + ... + N = 2020

We can use the formula for the sum of an arithmetic series:

Sum = (N/2) * (first term + last term)

Here, the first term is 1, and the last term is N.

2020 = (N/2) * (1 + N)

Now, we can simplify the equation and solve for N:

2020 = (N^2 + N) / 2

Multiplying both sides by 2:

4040 = N^2 + N

Rearranging the equation:

N^2 + N - 4040 = 0

Now, we can solve this quadratic equation using factoring, completing the square, or the quadratic formula. In this case, let's use factoring:

(N + 70)(N - 57) = 0

So, N + 70 = 0 or N - 57 = 0

N = -70 (not a natural number) or N = 57

Since we are looking for the smallest natural number, the value of N is 57.

Now, we can find 2N:

2N = 2 * 57 = 114

Therefore, N is 57, and 2N is 114.