Question

X²-3x-1-(2x²+3x-5)/2=1,5

Answer 1

${x}^{2} - 3x - 1 - \frac{2 {x}^{2} + 3x - 5}{2} = 1.5 \\ {x}^{2} - 3x - 1 - \frac{2 {x}^{2} + 3x - 5 }{2} - 1.5 = 0 \: \: \: | \times 10 \\ 10 {x}^{2} - 30x - 10 - 5(2 {x}^{2} + 3x - 5) - 15 = 0 \\ 10 {x}^{2} - 30x - 10 - 10 {x}^{2} - 15x + 25 - 15 = 0 \\ - 15x = 0 \\ x = 0$

Answer 2

To solve the equation:

x² - 3x - 1 - (2x² + 3x - 5)/2 = 1.5

Let's simplify the equation step by step:

1. Multiply both sides of the equation by 2 to get rid of the fraction:

2(x² - 3x - 1) - (2x² + 3x - 5) = 3

2x² - 6x - 2 - 2x² - 3x + 5 = 3

2x² - 2x² - 6x - 3x + 5 - 2 = 3

-9x + 3 = 3

2. Subtract 3 from both sides:

-9x = 3 - 3

-9x = 0

3. Divide both sides by -9:

x = 0 / -9

x = 0

Therefore, the solution to the equation is x = 0.