Question

Y²+6y+9=x²-2x-8=3x²-7x+43x²-7x+43x+10-x²=-4x²+7x=9a²-25=Разложите ​

Answer 1

Ответ:

у2+6у+9=у2+45

х2-2х-8=(×+4)×(х-2)

3х2-7х+4=(×-1)×(3×-4)

3х+10+10-×2=(×-5)×(×+2)

4×2+7×=х×(4х-7)

9а2-25=(3а-5 )×(3а+5)

Answer 2

It seems like you have provided a set of equations and expressions. To help you further, I'll address each of them separately and provide the solutions:

1. y² + 6y + 9 = 0: This is a quadratic equation. To solve for 'y,' we can factorize it as follows: (y + 3)(y + 3) = 0 (y + 3)² = 0 y + 3 = 0 y = -3

2. x² - 2x - 8 = 0: This is another quadratic equation. We can solve for 'x' by factorizing it: (x - 4)(x + 2) = 0 x - 4 = 0 or x + 2 = 0 x = 4 or x = -2

3. 3x² - 7x + 4 = 0: This is yet another quadratic equation. We can solve it by factorizing: (3x - 4)(x - 1) = 0 3x - 4 = 0 or x - 1 = 0 x = 4/3 or x = 1

4. 3x² - 7x + 43x² - 7x + 43x + 10 - x² = 0: Combine like terms: (3x² + 43x² - x²) + (-7x - 7x + 43x) + (10) = 0 (45x² - 15x + 10) = 0 Divide the entire equation by 5 to simplify: 9x² - 3x + 2 = 0

This quadratic equation cannot be factorized easily. To find the solutions for 'x,' we can use the quadratic formula: x = (-b ± √(b² - 4ac)) / 2a

Where a = 9, b = -3, and c = 2: x = (3 ± √((-3)² - 4 * 9 * 2)) / (2 * 9) x = (3 ± √(9 - 72)) / 18 x = (3 ± √(-63)) / 18

Since the expression inside the square root is negative, the solutions are complex numbers: x = (3 ± √(63)i) / 18 x = (1 ± √7i) / 6

5. -4x² + 7x = 0: Factor out 'x': x(-4x + 7) = 0 x = 0 or -4x + 7 = 0 x = 0 or -4x = -7 x = 0 or x = 7/4

6. 9a² - 25 = 0: This is a quadratic equation in 'a.' We can factorize it: (3a + 5)(3a - 5) = 0 3a + 5 = 0 or 3a - 5 = 0 3a = -5 or 3a = 5 a = -5/3 or a = 5/3

Remember that some of the equations have multiple solutions, and some have complex solutions. I hope this clarifies the solutions for the given equations and expressions. Let me know if you need any further assistance!