Question

(2х – 3)^2 – 3 = (2х + 1)^2 – 11 (^2 это степень)

Answer 1

$(2x - 3)^{2} - 3 = {(2x + 1)}^{2} - 11 \\ 4 {x}^{2} + 9 - 12x- 3 = 4 {x}^{2} + 1 + 4x - 11 \\ 4 {x}^{2} - 4x {}^{2} - 12x - 4x = 1 - 11 + 3 - 9 \\ - 16x = - 16 \\ 16x = 16 \\ x = 1$

Answer 2

To solve the equation, let's expand both sides and simplify:

(2x - 3)^2 - 3 = (2x + 1)^2 - 11

Expanding the squares:

(4x^2 - 12x + 9) - 3 = (4x^2 + 4x + 1) - 11

Removing parentheses:

4x^2 - 12x + 9 - 3 = 4x^2 + 4x + 1 - 11

Combining like terms:

4x^2 - 12x + 6 = 4x^2 + 4x - 10

Subtracting 4x^2 from both sides to eliminate the variable terms:

-12x + 6 = 4x - 10

Adding 12x to both sides:

6 = 16x - 10

Adding 10 to both sides:

16 = 16x

Dividing both sides by 16:

x = 1

So the solution to the equation is x = 1.