Question

X2+6xy+9y2-4x-12y+12 если х+3у=6 7 класс​

Answer 1

Ответ:

Объяснение:

(x+3)^2-4(x+3y-3)=6^2-4(6-3)=36-4*3=36-12=24

Answer 2

Ответ:

Прикрепила фотографию

Объяснение:

Answer 3

To find the value of the expression $X^2 + 6xy + 9y^2 - 4x - 12y + 12$ when $x + 3y = 6$, we need to substitute the value of $x + 3y$ into the expression.

Given: $x + 3y = 6$

We need to solve this equation for either $x$ or $y$ and then substitute the value into the expression. Let's solve for $x$:

$x = 6 - 3y$

Now, we can substitute this value of $x$ into the expression:

$X^2 + 6xy + 9y^2 - 4x - 12y + 12 = X^2 + 6(6 - 3y)y + 9y^2 - 4(6 - 3y) - 12y + 12$

Now, simplify the expression step by step:

$X^2 + 6(6 - 3y)y + 9y^2 - 4(6 - 3y) - 12y + 12 = X^2 + 6(6y - 3y^2) + 9y^2 - 24 + 12y + 12$

$X^2 + 6(6y - 3y^2) + 9y^2 - 24 + 12y + 12 = X^2 + 36y - 18y^2 + 9y^2 - 12 + 12y + 12$

$X^2 + 36y - 18y^2 + 9y^2 - 12 + 12y + 12 = X^2 + 27y - 18y^2 + 12$

So, the simplified expression is $X^2 + 27y - 18y^2 + 12$.

Please note that without knowing the specific values of $X$ or $y$, we can't determine the exact numerical result. This expression can be further simplified if more information is provided.