Question

(3+y) × y =4 дискримінант​

Answer 1

Ответ:

у2+3у-4=0

Д=9+16=25

х1=(-3+5):2=1

х2=-8:2=-4

Объяснение:

Answer 2

$\displaystyle \tt (3+y)\cdot y=4\\\\ \displaystyle \tt y^2+3y-4=0\\\\ \displaystyle \tt D=3^2-4\cdot1\cdot(-4)=9+16=25\\\\ \displaystyle \tt \sqrt{D}=\sqrt{25}=5\\\\ \displaystyle \tt \bold{x_1}=\frac{-3+5}{2}=\frac{2}{2}=1\\\\ \displaystyle \tt \bold{x_2}=\frac{-3-5}{2}=\frac{-8}{2}=-4$

Answer 3

To find the discriminant of the quadratic equation (3+y) × y = 4, we first need to rewrite it in standard quadratic form: ax^2 + bx + c = 0.

The given equation can be simplified as follows: (3 + y) × y = 4 3y + y^2 = 4 y^2 + 3y - 4 = 0

Now we can identify the coefficients: a = 1 (coefficient of y^2) b = 3 (coefficient of y) c = -4

The discriminant (Δ) of a quadratic equation of the form ax^2 + bx + c = 0 is given by Δ = b^2 - 4ac.

Let's calculate the discriminant for this equation: Δ = 3^2 - 4(1)(-4) Δ = 9 + 16 Δ = 25

So, the discriminant of the equation (3+y) × y = 4 is 25.