Question

X²-7x+6=0 2х²+3х+4=0​

Answer 1

2) из отрицательного квадратный корень не берётся

Answer 2

To solve the quadratic equations, let's use the quadratic formula:

For the equation x² - 7x + 6 = 0:

The quadratic formula is given by:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 1, b = -7, and c = 6.

Plugging in the values, we get:

x = (-(-7) ± √((-7)² - 4(1)(6))) / (2(1)) = (7 ± √(49 - 24)) / 2 = (7 ± √25) / 2 = (7 ± 5) / 2

So, we have two possible solutions:

x₁ = (7 + 5) / 2 = 12 / 2 = 6 x₂ = (7 - 5) / 2 = 2 / 2 = 1

Therefore, the solutions to x² - 7x + 6 = 0 are x = 6 and x = 1.

Now, let's solve the equation 2x² + 3x + 4 = 0:

Again, using the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Here, a = 2, b = 3, and c = 4.

Plugging in the values, we get:

x = (-(3) ± √((3)² - 4(2)(4))) / (2(2)) = (-3 ± √(9 - 32)) / 4 = (-3 ± √(-23)) / 4

Since we have a negative value under the square root, this equation has no real solutions. The solutions would be complex numbers.