Question

1) 10 11/24-X=6 7/102)(3/6+X)-2/3=13/10​

Answer 1

Объяснение:

1)

10 11/24-x=6 7/10

x= 10 11/24 - 6 7/10

x= 10 55/120 - 6 84/120

x= 3 91/120

Answer 2

To solve the equations, I'll break down the steps for each equation:

Equation 1: $10 \frac{11}{24} - X = 6 \frac{7}{102}$

Step 1: Convert mixed numbers to improper fractions. $10 \frac{11}{24} = \frac{10 \cdot 24 + 11}{24} = \frac{251}{24}$ $6 \frac{7}{102} = \frac{6 \cdot 102 + 7}{102} = \frac{619}{102}$

Step 2: Rewrite the equation with fractions. $\frac{251}{24} - X = \frac{619}{102}$

Step 3: Get a common denominator. The least common multiple of 24 and 102 is 1224.

$\frac{251 \cdot 51}{1224} - \frac{24 \cdot 619}{1224} = \frac{619 \cdot 12}{1224}$

Simplify the fractions. $\frac{12801}{1224} - \frac{14856}{1224} = \frac{7428}{1224}$

Step 4: Subtract the fractions and solve for X. $\frac{-2055}{1224} = \frac{7428}{1224} - X$

$X = \frac{7428 + 2055}{1224} = \frac{9483}{1224} = \frac{527}{68}$

Equation 2: $\left(\frac{3}{6} + X\right) - \frac{2}{3} = \frac{13}{10}$

Step 1: Simplify the fractions. $\frac{1}{2} + X - \frac{2}{3} = \frac{13}{10}$

Step 2: Get a common denominator. The least common multiple of 2 and 3 is 6.

$\frac{3}{6} \cdot \frac{3}{3} + X - \frac{4}{6} = \frac{39}{30}$

Simplify the fractions. $\frac{9}{6} + X - \frac{4}{6} = \frac{39}{30}$

Step 3: Combine fractions and solve for X. $\frac{5}{6} + X = \frac{13}{10}$

Subtract $\frac{5}{6}$ from both sides. $X = \frac{13}{10} - \frac{5}{6}$

Get a common denominator. $X = \frac{39}{30} - \frac{25}{30}$

$X = \frac{14}{30} = \frac{7}{15}$

So, the solutions are:

• For the first equation: $X = \frac{527}{68}$
• For the second equation: $X = \frac{7}{15}$