Question

1)8-4x=-4(-2) 2)-3x+9=0 3)5x-3=-10x 4)-7=5(x+5)

Answer 1

1) 8-4x=-4*(-2)
8-4x=8
-4x=8-8
-4x=0
x=0:(-4)
x=0


2) -3x+9=0
-3x=-9
x=-9:(-3)
x=3

3) 5x-3=-10x
5x+10x=3
15x=3
X=3/15
x=1/5


4) -7=5(x+5)
-7=5x+25
-7-25=5x
-32=5x
x=-(32/5)
X=-6,4

Answer 2

It looks like you've provided a set of equations. Did you want me to help you solve these equations? If so, I'd be happy to assist. Let's solve each equation step by step:

1. $8 - 4x = -4(-2)$:

First, distribute -4 to -2: $8 - 4x = 8$

Now subtract 8 from both sides: $-4x = 0$

Finally, divide both sides by -4: $x = 0$

So, the solution to this equation is $x = 0$.

2. $-3x + 9 = 0$:

Subtract 9 from both sides: $-3x = -9$

Divide both sides by -3: $x = 3$

The solution to this equation is $x = 3$.

3. $5x - 3 = -10x$:

Add $10x$ to both sides: $15x - 3 = 0$

Add 3 to both sides: $15x = 3$

Divide both sides by 15: $x = \frac{1}{5}$

So, the solution to this equation is $x = \frac{1}{5}$.

4. $-7 = 5(x + 5)$:

Distribute 5 to $x + 5$: $-7 = 5x + 25$

Subtract 25 from both sides: $5x = -32$

Divide both sides by 5: $x = -\frac{32}{5}$

The solution to this equation is $x = -\frac{32}{5}$.

If you have any more questions or need further assistance, feel free to ask!