Question

X²-4x+4 ———— 2x²-6x+4

Answer 1

На фото все расписала

Answer 2

$\frac{x^{2}-4x+4 }{2x^{2} -6x+4} =\frac{(x-2)^{2} }{2(x^{2} -3x+2)}=\frac{(x-2)^{2} }{2(x-1)(x-2)}=\frac{x-2}{2(x-1)} =\frac{x-2}{2x-2}$

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Answer 3

To simplify the expression (x² - 4x + 4) / (2x² - 6x + 4), we can factor both the numerator and denominator and cancel out common factors.

Numerator: x² - 4x + 4 The numerator can be factored as a perfect square trinomial: (x - 2)²

Denominator: 2x² - 6x + 4 The denominator can also be factored: 2(x - 1)(x - 2)

Now we can rewrite the expression:

(x² - 4x + 4) / (2x² - 6x + 4) = (x - 2)² / [2(x - 1)(x - 2)]

Note that (x - 2) appears in both the numerator and denominator, so we can cancel it out:

(x - 2)² / [2(x - 1)(x - 2)] = (x - 2) / [2(x - 1)]

Thus, the simplified expression is (x - 2) / [2(x - 1)].