Question

2cd^4 +3d -1,2d²-6d =с=3;d=-0,2​

Answer 1

Объяснение:

2*3*(-0,2)⁴+3(-0,2)-1,2(-,02)²-6(-0,2)=0,0096-0,6-0,048+1,2=0,5616

Answer 2

It looks like you have two equations:

1. 2cd^4 + 3d - 1 = c
2. 2d^2 - 6d = 3

And you want to solve for the variable 'd' when it's equal to -0.2.

Let's start by substituting d = -0.2 into the equations:

1. 2c(-0.2)^4 + 3(-0.2) - 1 = c
2. 2(-0.2)^2 - 6(-0.2) = 3

Now, let's simplify these equations:

1. 2c(0.0016) - 0.6 - 1 = c
2. 2(0.04) + 1.2 = 3

Simplify further:

1. 0.0032c - 0.6 - 1 = c
2. 0.08 + 1.2 = 3

Now, let's solve for 'c' in the first equation:

0.0032c - 0.6 - 1 = c

Combine like terms:

0.0032c - c = 0.6 + 1

Simplify:

-0.9968c = 1.6

Now, divide both sides by -0.9968 to solve for 'c':

c = 1.6 / (-0.9968) c ≈ -1.603

Now that we have the value of 'c', we can substitute it into the second equation:

2(-0.2)^2 - 6(-0.2) = 3

Simplify:

2(0.04) + 1.2 = 3

0.08 + 1.2 = 3

Now, combine like terms:

1.28 = 3

Since 1.28 is not equal to 3, the equation 2d^2 - 6d = 3 does not hold true when d = -0.2.

So, when d = -0.2, the value of 'c' is approximately -1.603, and the second equation is not satisfied.