Question

{x²-y=-1{2x+y=9хеееелп​ Смотреть ответ ksyuwi ksyuwi Ответ:             Проверка:

Answer 1

It seems like you've provided a system of two equations:

1. $x^2 - y = -1$
2. $2x + y = 9$

You would like to solve this system of equations for $x$ and $y$. Let's find the solution:

First, you can solve equation (2) for $y$:

$2x + y = 9$

Subtract $2x$ from both sides:

$y = 9 - 2x$

Now, you can substitute this expression for $y$ into equation (1):

$x^2 - (9 - 2x) = -1$

Expand and rearrange:

$x^2 + 2x - 8 = 0$

Now, you have a quadratic equation. To solve for $x$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, $a = 1$, $b = 2$, and $c = -8$. Plug these values into the formula:

$x = \frac{-2 \pm \sqrt{2^2 - 4(1)(-8)}}{2(1)}$

Simplify:

$x = \frac{-2 \pm \sqrt{4 + 32}}{2}$

$x = \frac{-2 \pm \sqrt{36}}{2}$

Now, take the square root of 36, which is 6:

$x = \frac{-2 \pm 6}{2}$

Now, you have two possible solutions for $x$:

1. $x = \frac{-2 + 6}{2} = 2$
2. $x = \frac{-2 - 6}{2} = -4$

Now that you have the values of $x$, you can find the corresponding values of $y$ using the equation $y = 9 - 2x$:

For $x = 2$: $y = 9 - 2(2) = 9 - 4 = 5$

For $x = -4$: $y = 9 - 2(-4) = 9 + 8 = 17$

So, the solutions to the system of equations are:

1. $x = 2$ and $y = 5$
2. $x = -4$ and $y = 17$

You can check these solutions by substituting them back into the original equations to ensure they satisfy both equations.