Question

(3x²y-4xy²)(3x²+4xy²)​

Answer 1

Ответ:

если тут надо упростить то вот : 9х⁴у+12х³у³-12х³у²-16х²у⁴

разложить на множители:"

Answer 2

To multiply the two expressions (3x²y - 4xy²) and (3x² + 4xy²), you can use the distributive property or the FOIL method (First, Outer, Inner, Last). Let's use the FOIL method:

(3x²y - 4xy²)(3x² + 4xy²)

First, multiply the First terms: (3x²y) * (3x²) = 9x^4y

Next, multiply the Outer terms: (3x²y) * (4xy²) = 12x³y³

Now, multiply the Inner terms: (-4xy²) * (3x²) = -12x⁴y²

Finally, multiply the Last terms: (-4xy²) * (4xy²) = -16x²y⁴

Now, add all these results together:

9x^4y + 12x³y³ - 12x⁴y² - 16x²y⁴

So, the product of (3x²y - 4xy²) and (3x² + 4xy²) is:

9x^4y + 12x³y³ - 12x⁴y² - 16x²y⁴