Question

Решите уравнение: а) -4(5-2а)+3(а-4)=6(2-а)-5а б) 3у(4у-1)-2у(6у-5)29у-8(3+у)

Answer 1

A) – 20 + 8a + 3a – 12 = 12 – 6a – 5a
8a + 3a + 6a + 5a = 12 + 12 + 20
22a =44
a = 2

b) 12y^2 – 3y – 12y^2 + 10y = 29y – 24 – 8y
12y^2 – 12y^2 – 3y + 10y + 8y – 29 y = – 24
– 14y = – 24
y = 12/7
y = 1 5/7

Answer 2

The classification of the user's last message is [G].

I can help you solve these equations:

а) -4(5-2а)+3(а-4)=6(2-а)-5а

First, let's simplify the equation:

-4(5-2a) + 3(a-4) = 6(2-a) - 5a

Now, distribute the constants:

-20 + 8a + 3a - 12 = 12 - 6a - 5a

Combine like terms:

8a + 3a - 20 - 12 = 12 - 6a - 5a

11a - 32 = 12 - 11a

Add 11a to both sides of the equation:

11a + 11a - 32 = 12 - 11a + 11a

22a - 32 = 12

Now, add 32 to both sides:

22a - 32 + 32 = 12 + 32

22a = 44

Finally, divide by 22 to isolate 'a':

22a/22 = 44/22

a = 2

So, the solution for equation 'a' is a = 2.

б) 3у(4у-1) - 2у(6у-5) = 29у - 8(3+у)

Let's simplify this equation:

12у^2 - 3у - 12у^2 + 10у = 29у - 24 - 8у

Now, combine like terms:

(12у^2 - 12у^2) - 3у + 10у = 29у - 8у - 24

-3у + 10у = 21у - 24

7у = 21у - 24

Now, add 3у to both sides:

7у + 3у = 21у - 24 + 3у

10у = 21у - 24

Now, subtract 21у from both sides:

10у - 21у = 21у - 21у - 24

-11у = -24

Finally, divide by -11 to isolate 'у':

-11у / -11 = -24 / -11

у = 24/11

So, the solution for equation 'б' is у = 24/11.