Question

1. 2x2-18=0; 2. 3x2+6x=0; 3. 5x2-10=0; 4. X2-7x=0; 5. 8x+4x2=0; 6. 3x2+25=0; 7. X2-4=0; 8. 16x2-1=0; 9. 6x2+7=12x=7.

Answer 1

Объяснение:

1. 2х²-18=0

2х²=18

х²=9

х1 = 3. х2 = -3.

2. 3х²+6х=0

3х(х+2)=0

х1 = 0. х2 = -2

3. 5х²-10=0

5х²=10

х²=2

х1 =

$x1.2 = \sqrt{2}$

4. х²-7х=0

х1=0 х2=7

5. 4х²+8х=0

4х(х+2)=0

х1 = 0. х2=-2

6. 3х²+25=0

3х²=-25

х²=8,333

$x1.2 = \sqrt{8.3333}$

7. х²-4=0

х²=4

х1,2 = 2

8. 16х²-1=0

16х²=1

х²=0,0625

х1,2 = 0,25

9. 6x2+7=12x=7.

6х²-12х=0

6х(х-2)=0

х1 = 0. х2 = 2

Answer 2

It looks like you have provided a list of equations. Some of them are quadratic equations, and others are not correctly formatted or have typographical errors. I will go through each of them and help you solve the quadratic equations:

1. $2x^2 - 18 = 0$ To solve this, first, add 18 to both sides: $2x^2 = 18$ Divide by 2: $x^2 = 9$ Take the square root of both sides: $x = \pm 3$

2. $3x^2 + 6x = 0$ Factor out the common factor, which is $3x$: $3x(x + 2) = 0$ Use the zero-product property: $3x = 0$ or $x + 2 = 0$ Solving, $x = 0$ or $x = -2$

3. $5x^2 - 10 = 0$ Add 10 to both sides: $5x^2 = 10$ Divide by 5: $x^2 = 2$ Take the square root of both sides: $x = \pm \sqrt{2}$

4. $x^2 - 7x = 0$ Factor out the common factor, which is $x$: $x(x - 7) = 0$ Use the zero-product property: $x = 0$ or $x - 7 = 0$ Solving, $x = 0$ or $x = 7$

5. $8x + 4x^2 = 0$ Factor out the common factor, which is $4x$: $4x(2 + x) = 0$ Use the zero-product property: $4x = 0$ or $2 + x = 0$ Solving, $x = 0$ or $x = -2$

6. $3x^2 + 25 = 0$ This equation has complex solutions because it cannot be factored further. The solutions are: $x = \pm \frac{\sqrt{25i}}{\sqrt{3}}$

7. $x^2 - 4 = 0$ Factor as the difference of squares: $(x - 2)(x + 2) = 0$ Use the zero-product property: $x - 2 = 0$ or $x + 2 = 0$ Solving, $x = 2$ or $x = -2$

8. $16x^2 - 1 = 0$ This equation can be factored as a difference of squares: $(4x - 1)(4x + 1) = 0$ Use the zero-product property: $4x - 1 = 0$ or $4x + 1 = 0$ Solving, $x = \frac{1}{4}$ or $x = -\frac{1}{4}$

9. The ninth equation appears to have a typo. It should be either $6x^2 + 7 = 12x$ or $6x^2 + 7x = 12$. Please clarify, and I can help you solve it.