Question

12х+ 7х +1 = 0; 2х+ 5х + 20 = 0; 10х- 5х – 0,6 = 0

Answer 1

Ответ:

це дискриминат Як думаю я

Answer 2

To solve each of these quadratic equations for x, you can use the quadratic formula:

For a quadratic equation of the form ax^2 + bx + c = 0, the quadratic formula is:

x = (-b ± √(b² - 4ac)) / (2a)

Let's solve each of the equations you've provided:

1. 12x + 7x + 1 = 0: Here, a = 12, b = 7, and c = 1.

   x = (-7 ± √(7² - 4121)) / (2*12) x = (-7 ± √(49 - 48)) / 24 x = (-7 ± √1) / 24

   x = (-7 ± 1) / 24

   x = (-7 + 1) / 24 = -6 / 24 = -1/4 x = (-7 - 1) / 24 = -8 / 24 = -1/3

So, the solutions for this equation are x = -1/4 and x = -1/3.

2. 2x + 5x + 20 = 0: Here, a = 2, b = 5, and c = 20.

   x = (-5 ± √(5² - 4220)) / (2*2) x = (-5 ± √(25 - 160)) / 4 x = (-5 ± √(-135)) / 4

Since the discriminant (the value inside the square root) is negative, this equation has complex solutions. You can express the solutions as:

x = (-5 ± √135i) / 4, where "i" represents the imaginary unit.

3. 10x - 5x - 0.6 = 0: Here, a = 10, b = -5, and c = -0.6.

   x = (5 ± √((-5)² - 410(-0.6))) / (2*10) x = (5 ± √(25 + 24)) / 20 x = (5 ± √49) / 20 x = (5 ± 7) / 20

   x = (5 + 7) / 20 = 12 / 20 = 3/5 x = (5 - 7) / 20 = -2 / 20 = -1/10

So, the solutions for this equation are x = 3/5 and x = -1/10.