Question

(x+3)²-2(x+3)-8=0Розвяжить ривняння​

Answer 1

Ответ:

делаешь замену t=x+3, тогда

t^2-2t-8=0

t=4

t=-2

Делаешь обратную замену,

х+3=4;

x+3=-2;

x=1

x=-5

Объяснение:

Answer 2

Sure, let's solve the quadratic equation $(x+3)^2 - 2(x+3) - 8 = 0$.

First, let's simplify it:

$(x+3)^2 - 2(x+3) - 8 = 0$

Expand $(x+3)^2$:

$x^2 + 6x + 9 - 2(x+3) - 8 = 0$

Distribute the $-2$:

$x^2 + 6x + 9 - 2x - 6 - 8 = 0$

Combine like terms:

$x^2 + 4x - 5 = 0$

Now, we can solve for $x$. This quadratic equation can be factored as $(x + 5)(x - 1) = 0$, so the solutions are $x = -5$ and $x = 1$.