Question

Задайте формулой функцию, график которой проходит через точку (0; 3) и параллелен графику функции y = –4x. ДАЮ 50 БАЛОВ!!!!!!!!!

Answer 1

Смотри......................

Answer 2

Finding a Function Parallel to y = -4x and Passing Through the Point (0, 3)

To find a function that is parallel to the graph of y = -4x and passes through the point (0, 3), we can use the point-slope form of a linear equation. The point-slope form is given by:

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope of the line.

In this case, the slope of the line y = -4x is -4. Since we want a line parallel to this, the slope of the new line will also be -4. The point (0, 3) is given, so we can substitute these values into the point-slope form:

y - 3 = -4(x - 0)

Simplifying the equation, we have:

y - 3 = -4x

This is the equation of the function that is parallel to y = -4x and passes through the point (0, 3).

Graph of the Function

To visualize the graph of the function, we can plot a few points and connect them with a straight line. Since the equation is linear, we only need two points to determine the line.

Let's choose two x-values and find the corresponding y-values using the equation y = -4x.

When x = 1: y = -4(1) = -4

When x = -1: y = -4(-1) = 4

So, we have two points: (1, -4) and (-1, 4). We can plot these points on a graph and connect them with a straight line.

Here is the graph of the function that is parallel to y = -4x and passes through the point (0, 3):


The blue line represents the graph of the function y = -4x, and the red line represents the graph of the function parallel to y = -4x and passing through the point (0, 3).

I hope this helps! Let me know if you have any further questions.