
Помогите плиз Срочно если я не решу мне Хана За 4 часа катер проходит по течению на 20 км меньше,
чем за 10 ч против течения. Какова скорость катера в стоячей воде 15 км/ч?

Ответы на вопрос

Ответ:
не понятно так как " 15 км/ч " что это сам ответ или же что???



Calculation of the Boat's Speed in Still Water
To calculate the speed of the boat in still water, we can use the concept of relative velocity. Let's assume the speed of the boat in still water is x km/h.
According to the given information, the boat takes 4 hours to travel a certain distance with the current and 10 hours to travel the same distance against the current. The speed of the current is given as 20 km/h.
When the boat is traveling with the current, its effective speed is increased by the speed of the current. Therefore, the boat's speed with the current is (x + 20) km/h.
When the boat is traveling against the current, its effective speed is decreased by the speed of the current. Therefore, the boat's speed against the current is (x - 20) km/h.
We can set up the following equation based on the given information:
Distance = Speed × Time
Using this equation, we can set up two equations:
1. When the boat is traveling with the current: Distance = (x + 20) km/h × 4 hours
2. When the boat is traveling against the current: Distance = (x - 20) km/h × 10 hours
Since the distance traveled is the same in both cases, we can equate the two equations:
(x + 20) km/h × 4 hours = (x - 20) km/h × 10 hours
Simplifying the equation:
4(x + 20) = 10(x - 20)
Solving for x:
4x + 80 = 10x - 200
6x = 280
x = 280/6
x ≈ 46.67 km/h
Therefore, the speed of the boat in still water is approximately 46.67 km/h.
Please note that the calculation is based on the given information and assumptions.


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