Question

Поезд подходит к станции со скоростью 54 км/ч и останавливается через минуту после начала торможения. С каким ускорением двигался поезд? ​

Answer 1

Ответ:

−0,25 м/c^2

Объяснение:

54км/ч = 15м/c

1 мин = 60 сек

a= v-v0/t

a= 0-15/60

a= -0.25

Answer 2

Calculating Train's Deceleration

To calculate the train's deceleration, we can use the following kinematic equation:

v = u + at

Where: - v = final velocity (0 km/h, as the train stops) - u = initial velocity (54 km/h) - a = acceleration (deceleration in this case, denoted by a negative value) - t = time taken to stop (1 minute, which we'll convert to hours for consistency)

First, let's convert the initial velocity and time to SI units: - Initial velocity, u = 54 km/h = 15 m/s - Time, t = 1 minute = 1/60 hours

Now, we can rearrange the equation to solve for acceleration: a = (v - u) / t

Substituting the values: a = (0 - 15) / (1/60) a = -900 / 1 a = -900 m/s^2

So, the train decelerated at an acceleration of -900 m/s^2.