Question

Швидкість пароплаву — 36 км/год . Скільки обертів за хвилину роблять колеса двигуна, радіус яких — 4 м. ОЧЕНЬ СРОЧНО!!! КАК МОЖНО БЫСТРЕЕ!!!

Answer 1

Дано: V=36 км/ч=10 м/с; R=4 м; t=60 с; n - ?

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n=S/(2πR)=V*t/(2πR)=

10*60/(2π*4)=600/(8π)=75/3,14≈23,88≈24 оборота.

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Можно и в минутах.

V=36 км/ч=600 м/мин; t=1 мин; R=4 м; n - ?

n=V*t/(2πR)=600*1/(8π)≈24 оборота.

Answer 2

Calculating the Speed of the Steamship's Engine Wheels

The question asks us to calculate the number of revolutions per minute (RPM) of the engine wheels on a steamship given:

The speed of the steamship is 36 km/h (kilometers per hour) The radius of each engine wheel is 4 m (meters)

To solve this, let's break it down step-by-step:

1. Convert the steamship's speed from km/h to m/s (meters per second): 36 km/h = 10 m/s

2. Use the formula for circumferential speed (speed of the outer edge of a wheel) to relate the speed of the steamship to the RPM of the wheels: Circumferential Speed = 2πr × RPM Where: - r is the radius of the wheel (given as 4m) - π is approximately 3.14159

3. Plug in the values and solve for RPM: 10 m/s = 2π × 4 m × RPM RPM = 10 m/s / (2π × 4 m) RPM = 10 / (2π × 4) RPM = 10 / 25.1328 RPM = approximately 0.4 RPM

Therefore, the number of revolutions per minute of the engine wheels is 0.4 RPM.