Question

8. Груз массой 1,8 кг равномерно переместили к вершине наклонной плоскости длиной 4,8 м и высотой 1,2 м. При этом была приложена сила 25 Н. Каков КПД установки?

Answer 1

Ответ:

Объяснение:.....

Answer 2

Calculation of Efficiency (КПД) of the System

To calculate the efficiency (КПД) of the system, we need to determine the work input and work output of the system.

The work input (W_in) is given by the formula:

W_in = F * d

where F is the applied force and d is the distance over which the force is applied.

In this case, the applied force is 25 N and the distance over which the force is applied is the length of the inclined plane, which is 4.8 m.

W_in = 25 N * 4.8 m

The work output (W_out) is given by the formula:

W_out = m * g * h

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the inclined plane.

In this case, the mass of the object is 1.8 kg, the acceleration due to gravity is approximately 9.8 m/s^2, and the height of the inclined plane is 1.2 m.

W_out = 1.8 kg * 9.8 m/s^2 * 1.2 m

Now, we can calculate the efficiency (КПД) of the system using the formula:

Efficiency (КПД) = (W_out / W_in) * 100%

Let's calculate the efficiency (КПД) of the system:

F = 25  # Applied force in Newtons
d = 4.8  # Distance over which the force is applied in meters
m = 1.8  # Mass of the object in kilograms
g = 9.8  # Acceleration due to gravity in m/s^2
h = 1.2  # Height of the inclined plane in meters

W_in = F * d
W_out = m * g * h

efficiency = (W_out / W_in) * 100

efficiency

The efficiency (КПД) of the system is approximately 92.16%.

Please note that this calculation assumes no energy losses due to friction or other factors.