Question

Помогите пожалуйста Тело растянуло в воздухе пружину динамометра с силой 109,7 H, а в воде — с силой 4,7н. Чему равен объем тела? M (Принять у г 10 м/с2), Ответ (округли до десятых); объем тела равен ди",

Answer 1

Ответ: 0,0105м³

Объяснение:

Дано:

F1=109,7Н

F2=4,7Н

g=10Н/кг

ρ=1000кг/м³

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V-?

Fa=F1-F2=109,7-4,7=105Н

Fa=ρgV

V=Fa/(ρg)=105/(1000*10)=0,0105м³

Answer 2

Calculation of Volume of the Object

To calculate the volume of the object, we can use the principle of buoyancy. The difference in the force exerted by the object in air and in water can be used to calculate the volume of the object.

Given: - Force in air (F_air) = 109.7 N - Force in water (F_water) = 4.7 N - Acceleration due to gravity (g) = 10 m/s^2

Solution

The buoyant force experienced by the object in water can be calculated using the formula: Buoyant force = Weight of the water displaced = Volume of the object * Density of water * g

The weight of the object in air is given by the force exerted in air: Weight in air = F_air = Volume of the object * g

The weight of the object in water is given by the force exerted in water: Weight in water = F_water = (Volume of the object * Density of water * g) - (Volume of the object * g)

Solving for the volume of the object: Volume of the object = F_air / g

Let's calculate the volume of the object using the given values.