Question

персей решил поднять тяжолое тело массой 90кг на высоту 3м. Для этого он толкал данное тело с помощью наклонной плоскости с силой 400Н на пути 5 метров. определите КПД данной наклоности плоскости (g=10Н/кг)​

Answer 1

Ответ: Кпд 13.5%

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m=90кг

h=0.3м

g=10Н/кг

F=400H

S=5м

n-?

n=Aпол/Азат->mgh/Fs->90*10*0.3/400*5=13.5%

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Answer 2

Calculation of Efficiency (КПД)

To calculate the efficiency (КПД) of the inclined plane, we need to determine the work input and the work output.

Given information: - Mass of the heavy object (m): 90 kg - Height lifted (h): 3 m - Force applied (F): 400 N - Distance over which the force is applied (d): 5 m - Acceleration due to gravity (g): 10 N/kg

Work Input (Входная работа)

The work input is the product of the force applied and the distance over which the force is applied. It can be calculated using the formula:

Work Input (Входная работа) = Force (F) × Distance (d)

Substituting the given values:

Work Input = 400 N × 5 m

Calculating the work input:

Work Input = 2000 J

Work Output (Выходная работа)

The work output is the product of the weight of the object and the height lifted. It can be calculated using the formula:

Work Output (Выходная работа) = Weight (m × g) × Height (h)

Substituting the given values:

Work Output = (90 kg × 10 N/kg) × 3 m

Calculating the work output:

Work Output = 2700 J

Efficiency (КПД)

Efficiency is the ratio of the work output to the work input, expressed as a percentage. It can be calculated using the formula:

Efficiency (КПД) = (Work Output / Work Input) × 100

Substituting the calculated values:

Efficiency = (2700 J / 2000 J) × 100

Calculating the efficiency:

Efficiency = 135%

The efficiency of the inclined plane in this scenario is 135%.

Please note that the efficiency value obtained is greater than 100%. This may be due to rounding errors or inaccuracies in the given values or calculations.