Question

5. Площадь меньшего поршня гидравлического пресса 25 см2, площадь большего поршня 500 см2 На меньший поршеньдействует сила 750 Н. Какая сила действует на больший поршень?​

Answer 1

Ответ:

F1/F2=S1/S2

F2=F1*S2/S1=350*300/15=7000H

Объяснение:

Answer 2

Calculation of Force on the Larger Piston in a Hydraulic Press

To calculate the force exerted on the larger piston in a hydraulic press, we can use the principle of Pascal's law, which states that the pressure exerted on a fluid is transmitted equally in all directions.

Given: - Area of the smaller piston (A1) = 25 cm² - Area of the larger piston (A2) = 500 cm² - Force on the smaller piston (F1) = 750 N

We can use the formula:

F2 = (A2 / A1) * F1

where: - F2 is the force exerted on the larger piston - A2 is the area of the larger piston - A1 is the area of the smaller piston - F1 is the force on the smaller piston

Substituting the given values into the formula, we can calculate the force on the larger piston:

F2 = (500 cm² / 25 cm²) * 750 N

Calculating this expression:

F2 = 30 * 750 N

F2 = 22,500 N

Therefore, the force exerted on the larger piston is 22,500 N.