Question

идеальный  одноатомный газ количество вещества которого равно 2 моль,сжали изобарно так,что его объем уменьшился в 3 раза вычислить работу,которая совершается внешними силами над газом,когда начальная температура равна 77 градусов .оооочень нужно!!!!!!

Answer 1

Работа при изобарном сжатии вычисляется по формуле
А= ню*R * ( T1- T2)
Начальная температураT1 = 77+273= 350 K
Из уравнения Клапейрона находим вторую температуру она равна T2= 150К
Вычисляем работу A= 2* 8.31*(350-150)=3324 Дж= 3,324 кДж

Answer 2

Ideal Gas Law and Work Done on a Gas

To calculate the work done on a gas, we need to use the ideal gas law and the equation for work done in an isobaric process.

The ideal gas law relates the pressure, volume, and temperature of an ideal gas. It is given by the equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas

In an isobaric process, the pressure of the gas remains constant. Therefore, the work done on the gas can be calculated using the equation:

W = PΔV

Where: - W is the work done on the gas - P is the constant pressure - ΔV is the change in volume of the gas

Calculation of Work Done on the Gas

In this case, we have an ideal gas with a quantity of substance (number of moles) equal to 2 mol. The gas is compressed isobarically, reducing its volume by a factor of 3. The initial temperature of the gas is 77 degrees.

To calculate the work done on the gas, we need to determine the initial and final volumes of the gas.

Given that the initial volume of the gas is V and it is reduced by a factor of 3, the final volume of the gas is V/3.

Now, we can calculate the work done on the gas using the equation:

W = PΔV

Since the pressure of the gas remains constant, we can substitute P with nRT/V, where n is the number of moles, R is the ideal gas constant, and T is the temperature.

W = (nRT/V)ΔV

Substituting the given values: - n = 2 mol - R = ideal gas constant - T = 77 degrees (convert to Kelvin by adding 273.15) - V = initial volume

We can now calculate the work done on the gas.

Let's proceed with the calculation.