Question

A  force  of  200 N stretches  a  spring  by  4 m.  What  is  the  value  of  the  spring  constant?​

Answer 1

Ответ:

Объяснение:

Дано:

F = 200 H

Δx = 4 м

_________

k - ?

Жесткость пружины:

k = F / Δx = 200 / 4 = 50 Н/м

Answer 2

To find the spring constant (k), you can use Hooke's Law, which relates the force applied to a spring to its displacement. Hooke's Law is given by:

F = -kx

Where:

• F is the force applied to the spring (in Newtons, N).
• k is the spring constant (in Newtons per meter, N/m).
• x is the displacement from the equilibrium position (in meters, m).

In your case, the force (F) is 200 N, and the displacement (x) is 4 m. You want to find the spring constant (k). Rearrange Hooke's Law to solve for k:

k = -F / x

Now, plug in the values:

k = -200 N / 4 m

k = -50 N/m

So, the spring constant (k) is 50 N/m. Note that the negative sign indicates that the force is acting in the opposite direction of the displacement from the equilibrium position.