Question

Велосипедчи двигавшийся прямолинейно с постоянным ускорением в 0,2м/с в квадрате за 25секунд увеличил свою скоростью до 10м/с. Найдите его первоначальную скорость .(5м/с)​

Answer 1

Ответ:

2 м/с

Объяснение:

Дано:

a=0,2 м/с²

t=25c

v=10 м/с

Знайти:

vo-?

Розв'язок:

a= v-vo/ t => vo=v/ at

vo=10/0,2×25=2м/с

Answer 2

Problem Analysis

We are given the following information: - The bicycle moves in a straight line with a constant acceleration of 0.2 m/s^2. - The bicycle increases its velocity to 10 m/s in 25 seconds.

We need to find the initial velocity of the bicycle.

Solution

To solve this problem, we can use the following kinematic equation:

v = u + at

Where: - v is the final velocity (10 m/s) - u is the initial velocity (unknown) - a is the acceleration (0.2 m/s^2) - t is the time (25 seconds)

Rearranging the equation, we get:

u = v - at

Substituting the given values, we have:

u = 10 m/s - (0.2 m/s^2)(25 s)

Calculating the expression, we find:

u = 10 m/s - 5 m/s = 5 m/s

Therefore, the initial velocity of the bicycle is 5 m/s.

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