Question

Автомобіль рухається прямолінійно зміна його шляху описується рівнянням l=15-3t Знайти: -Початкову швидкість автомобіля -Координату автомобіля через 3 секунди після початку руху -Прискорення, з яким рухається автомобіль -Вид руху автомобіля З поясненням

Answer 1

Уравнение движения x(t)=xo+vt x(t)=15-3t xo=15 м - начальная координата. v=-3 м/с - скорость. Движение равномерное с постоянной скоростью. Ускорение = 0. Координата через 3 секунды: x(3)=15-3*3=6 м. Тело двигалось из точки с координатой 15 м против оси координаты со скоростью 3 м/с, поэтому через 3 с оказалось в точке с координатой 6 м. Ответ: -3 м/с; 6 м; 0; равномерное. Скорость - 3 м/с или 3 м/с против оси координат - одно и тоже.

Answer 2

I'm sorry, I could not find any web search results that match your query exactly. However, I can try to answer your question using some similar questions that I found on the web. Here is what I found:

- The equation of motion for a car moving in a straight line is l = 15 - 3t, where l is the distance traveled in meters and t is the time in seconds. To find the initial velocity, acceleration, and type of motion of the car, we need to use the following formulas:

* The initial velocity (v0) is the value of the velocity function (v) when t = 0. The velocity function is the derivative of the distance function, so v = dl/dt = -3. Therefore, v0 = -3 m/s. * The acceleration (a) is the rate of change of the velocity function, or the second derivative of the distance function. So a = dv/dt = d^2l/dt^2 = 0. Therefore, a = 0 m/s^2. * The type of motion depends on the sign and value of the acceleration. Since the acceleration is zero, the motion is uniform, meaning that the velocity is constant and the distance changes linearly with time.

- To find the coordinate of the car after 3 seconds of motion, we need to plug in t = 3 into the distance function and get the value of l. So l = 15 - 3(3) = 6 m. This means that the car has traveled 6 meters from its starting point in the negative direction (since the velocity is negative).

Here is a summary of the answer:

- The initial velocity of the car is -3 m/s. - The coordinate of the car after 3 seconds is 6 m. - The acceleration of the car is 0 m/s^2. - The type of motion of the car is uniform.