Question

Помогите срочно пожалуйста очень надо Поршень гидравлического пресса площадью 180 2см- действует на сдавливаемое тело с силой 18 кН. Площадь малого поршня 5 см2. Найди, с какой силой действует меньший поршень на масло в прессе. - Ответ (округли до десятых): меньший поршень действует с силой Н.​

Answer 1

Надеюсь здесь будет всё понятно.

Answer 2

Hydraulic Press Force Calculation

To calculate the force exerted by the smaller piston on the oil in the press, we can use the principle of Pascal's law, which states that the pressure applied to a fluid in a closed system will be transmitted equally in all directions.

Pascal's law states that the pressure applied to a fluid in a closed system will be transmitted equally in all directions.

The formula to calculate the force exerted by the smaller piston is:

Force = Pressure × Area

Where: - Force is the force exerted by the smaller piston. - Pressure is the pressure applied by the larger piston. - Area is the area of the smaller piston.

Calculation

Given: - Area of the larger piston (A1) = 180 cm^2 - Force applied by the larger piston (F1) = 18 kN - Area of the smaller piston (A2) = 5 cm^2

First, we need to calculate the pressure applied by the larger piston using the formula:

Pressure = Force / Area

Substitute the given values: Pressure = 18 kN / 180 cm^2

Now, we can calculate the pressure: Pressure = 0.1 kN/cm^2

Now, we can calculate the force exerted by the smaller piston using the formula: Force = Pressure × Area

Substitute the calculated pressure and the area of the smaller piston: Force = 0.1 kN/cm^2 × 5 cm^2

Now, we can calculate the force exerted by the smaller piston: Force = 0.5 kN

So, the force exerted by the smaller piston on the oil in the press is approximately 0.5 kN (rounded to the nearest tenth).

Therefore, the smaller piston exerts a force of approximately 0.5 kN on the oil in the press.