Question

НОК (75,60) НОК(180,45,60) НОК (12,35)​

Answer 1

Ответ:

нок(75,60) - 300

нок(180,45,60) - 2160

нок(12,35) - 420

Answer 2

НОК (75,60)
75 = 3•5•5
60 = 2•2•3•5
НОК (75,60) = 2•2•3•5•5= 300

НОК(180,45,60)
180 = 2•2•3•3•5
45 = 3•3•5
60 = 2•3•3•5
НОК(180,45,60 = 2•2•3•3•5 = 180

НОК (12,35)
12 = 2•2•3
35 = 5•7
НОК (12,35) = 2•2•3•5•7 = 420

Answer 3

It looks like you're asking for the least common multiples (LCM) of certain numbers. The LCM is the smallest multiple that is evenly divisible by all the given numbers. Let's calculate the LCM for the sets of numbers you provided:

1. LCM(75, 60): To find the LCM of 75 and 60, we need to find the prime factors of each number and then take the highest power of each prime factor.

75 = 3^1 * 5^2 60 = 2^2 * 3^1 * 5^1

Now, we take the highest power of each prime factor: 2^2 * 3^1 * 5^2 = 300

So, the LCM of 75 and 60 is 300.

2. LCM(180, 45, 60): To find the LCM of 180, 45, and 60, we'll again find the prime factors of each number and then take the highest power of each prime factor.

180 = 2^2 * 3^2 * 5^1 45 = 3^2 * 5^1 60 = 2^2 * 3^1 * 5^1

Taking the highest power of each prime factor: 2^2 * 3^2 * 5^1 = 180 * 1 = 180

So, the LCM of 180, 45, and 60 is 180.

3. LCM(12, 35): To find the LCM of 12 and 35, we'll once again find the prime factors of each number and then take the highest power of each prime factor.

12 = 2^2 * 3^1 35 = 5^1 * 7^1

Taking the highest power of each prime factor: 2^2 * 3^1 * 5^1 * 7^1 = 2^2 * 3^1 * 5^1 * 7^1 = 420

So, the LCM of 12 and 35 is 420.

To summarize:

1. LCM(75, 60) = 300
2. LCM(180, 45, 60) = 180
3. LCM(12, 35) = 420

If you have any more sets of numbers or further questions, feel free to ask!