Question

От базы до первого привала турист шёл 1 4/5 ч. Определи расстояние,которое прошёл турист, если его средняя скорость равна 4 7/9 км ч (В ответе дробь сократи!) Ответ: турист прошёл расстояние . . . км. РЕШИТЕ ЗАДАЧУ МОЖЕТЕ НАПИСАТЬ ТОЛЬКО ОТВЕТ СРОЧНО!!! 20 баллов

Answer 1

Ответ:

S = v * t — формула пути.

t = 1 4/5 ч = 9/5 ч — время в пути.

v = 4 7/9 км/ч = 43/9 км/ч — средняя скорость.

S = 43/9 * 9/5 = 43/5 = 8 3/5 км — расстояние.

Ответ: 8 3/5 км.

Пошаговое объяснение: правильно. если не трудно, поставь спасибо пожалуйста

Answer 2

Problem Analysis

The problem states that a tourist walked from a starting point to the first rest stop in 1 4/5 hours. The average speed of the tourist is given as 4 7/9 km/h. We need to determine the distance the tourist traveled.

Solution

To find the distance traveled, we can use the formula:

Distance = Speed × Time

Let's calculate the distance using the given information.

Calculation

Given: - Time = 1 4/5 hours - Speed = 4 7/9 km/h

First, let's convert the time to an improper fraction: 1 4/5 = (5 × 1 + 4) / 5 = 9/5

Next, let's convert the speed to an improper fraction: 4 7/9 = (9 × 4 + 7) / 9 = 43/9

Now, we can calculate the distance: Distance = Speed × Time Distance = (43/9) × (9/5) Distance = (43 × 9) / (9 × 5) Distance = 387 / 45

To simplify the fraction, we can find the greatest common divisor (GCD) of 387 and 45, which is 3. Dividing both the numerator and denominator by 3, we get: Distance = (387 ÷ 3) / (45 ÷ 3) Distance = 129 / 15

Therefore, the tourist traveled a distance of 129/15 km.

Answer

The tourist traveled a distance of 129/15 km.

Note: The answer is provided as a fraction, as requested in the problem.