Question

Опять задача, пожалуйста! Рома Дима и Костя кушали яблоки. Рома съел в 2 раза больше, чем Костя, а Костя, на 11 меньше, чем Дима. Сколько яблок съел Дима, если всего они съели 23 яблока? На помощь!!

Answer 1

Ответ:

14 яблок

Объяснение:

Дима - х яблок, Костя - (х-11), Рома - 2*(х-11)

х+(х-11)+2*(х-11)=23

х+х-11+2х-22=23

х+х+2х=23+22+11

4х=56

х=56/4

х=14

Answer 2

Problem Analysis

We are given that Roma, Dima, and Kostya ate apples. Roma ate twice as many as Kostya, and Kostya ate 11 fewer than Dima. We need to determine how many apples Dima ate if they ate a total of 23 apples.

Solution

Let's assume that Kostya ate x apples. According to the problem, Roma ate twice as many as Kostya, so Roma ate 2x apples. Additionally, Kostya ate 11 fewer apples than Dima, so Dima ate x + 11 apples.

The total number of apples eaten is given as 23, so we can write the equation:

x + 2x + (x + 11) = 23

Simplifying the equation:

4x + 11 = 23

Subtracting 11 from both sides:

4x = 12

Dividing both sides by 4:

x = 3

Therefore, Kostya ate 3 apples, Roma ate 2 * 3 = 6 apples, and Dima ate 3 + 11 = 14 apples.

Answer

Dima ate 14 apples.

Explanation

According to the given information, Kostya ate 3 apples, Roma ate 6 apples, and Dima ate 14 apples. This satisfies the conditions mentioned in the problem statement.

Please let me know if anything is unclear or if you need further assistance!