Question

Розв'яжи рівняння: 1)36к²-60к+25=0 2)6х³-24к=0 МЕНІ ПОТРІБНА ПОВНА ВДПОВІДЬ!!!! просто число яке вийде мені не потрібне(буду кидати жалоби!!)

Answer 1

Объяснение:

1)

$36k {}^{2} - 60k + 25 = 0$

$(6k - 5) {}^{2} = 0$

$6k - 5 = 0$

k=5/6

2)

$6x {}^{3} - 24x = 0$

$6x(x {}^{2} - 4) = 0$

$x( x {}^{2} - 4) = 0$

$x = 0 \\ x {}^{2} - 4 = 0$

$x = 0 \\ x = - 2 \\ x = 2$

Answer 2

Solving the Equations:

To solve the given equations, let's go through each one step by step:

Equation 1: 36к² - 60к + 25 = 0

To solve this quadratic equation, we can use the quadratic formula:

к = (-b ± √(b² - 4ac)) / (2a)

Comparing the equation with the standard quadratic form ax² + bx + c = 0, we can identify: a = 36, b = -60, and c = 25.

Now, let's substitute these values into the quadratic formula and solve for к:

к = (-(-60) ± √((-60)² - 4 * 36 * 25)) / (2 * 36)

Simplifying further:

к = (60 ± √(3600 - 3600)) / 72

к = (60 ± √0) / 72

Since the discriminant (√(b² - 4ac)) is zero, the equation has only one solution:

к = 60 / 72

Simplifying the fraction:

к = 5 / 6

Therefore, the solution to Equation 1 is к = 5/6.

Equation 2: 6х³ - 24к = 0

To solve this equation, we can factor out the common factor of 6:

6(х³ - 4к) = 0

Now, we have:

х³ - 4к = 0

To find the values of х and к that satisfy this equation, we need more information. If you provide the value of either х or к, we can solve for the other variable.