Question

Периметр прямокутника дорівнює 144, причому його довжина в пять раз більша за ширину . Знайти сторони прямокутника та його площу .​

Answer 1

Объяснение:

144:2=72 напівпериметр прямокутника

Нехай ширина х, довжина 5х.

х+5х=72;  6х=72;  х=12.

Ширина 12, довжина 60.

Площа=12*60=720 од².

Answer 2

Problem Analysis

We are given that the perimeter of a rectangle is 144 units and that its length is five times greater than its width. We need to find the dimensions of the rectangle and its area.

Solution

Let's assume that the width of the rectangle is x units. According to the given information, the length of the rectangle is five times greater than its width, so the length would be 5x units.

The perimeter of a rectangle is given by the formula: perimeter = 2(length + width). We are given that the perimeter is 144 units, so we can set up the equation as follows:

144 = 2(5x + x)

Simplifying the equation, we get:

144 = 2(6x)

Dividing both sides of the equation by 2, we have:

72 = 6x

Now, we can solve for x:

x = 72/6 = 12

So, the width of the rectangle is 12 units.

The length of the rectangle is five times greater than the width, so the length would be:

5x = 5 * 12 = 60

Therefore, the length of the rectangle is 60 units.

To find the area of the rectangle, we use the formula: area = length * width. Substituting the values we found, we have:

area = 60 * 12 = 720

Therefore, the area of the rectangle is 720 square units.

Answer

The width of the rectangle is 12 units, the length is 60 units, and the area is 720 square units.