Question

Розкласти на множники. 2) 6m - 6n + am - an; ; 4) х2 + Зах – 2x – 6а 6) 5a - 5b + ap - bp; 8) a - 1 + ab – b;114)x5 - 3x3 + 4x2 – 12 пожалуйста​

Answer 1

Объяснение:

2)6m+am-6n-an=m(6+a)-n(6+a)=(m-n)(6+a)

4)x²-2x+3ax-6a=x(x-2)+3a(x-2)=(x+3a)(x-2)

6)5a-5b+ap-bp=5(a-b)+p(a-b)=(5+p)(a-b)

8)a-1+ab-b=1•(a-1)+b(a-1)=(b+1)(a-1)

14)x⁵-3x³+4x²-12=x³(x²-3)+4(x²-3)=(x²+4)(x²-3)=(x²+4)(x-√3)(x+√3)

Answer 2

Factoring Expressions:

1) To factor the expression 2 + 6m - 6n + am - an, we can group the terms: (2 + am) + (6m - an) - 6n Now, we can factor out the common factors from each group: 2(1 + a) + 6m(1 - a) - 6n The factored form of the expression is: 2(1 + a) + 6m(1 - a) - 6n.

2) To factor the expression х^2 - 2x - 6а, we can use the quadratic formula or factor by grouping. Let's use the quadratic formula: The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / (2a) For the given expression, a = 1, b = -2, and c = -6. Plugging in these values into the quadratic formula, we get: x = (-(-2) ± √((-2)^2 - 4(1)(-6))) / (2(1)) Simplifying further, we have: x = (2 ± √(4 + 24)) / 2 x = (2 ± √28) / 2 x = (2 ± 2√7) / 2 x = 1 ± √7 Therefore, the factored form of the expression is: (x - (1 + √7))(x - (1 - √7)).

3) To factor the expression 5a - 5b + ap - bp, we can group the terms: (5a + ap) - (5b - bp) Now, we can factor out the common factors from each group: 5a(1 + p) - 5b(1 - p) The factored form of the expression is: 5a(1 + p) - 5b(1 - p).

4) To factor the expression a - 1 + ab - b, we can group the terms: (a + ab) - (1 + b) Now, we can factor out the common factors from each group: a(1 + b) - 1(1 + b) The factored form of the expression is: a(1 + b) - 1(1 + b).

5) To factor the expression x^5 - 3x^3 + 4x^2 - 12, we can look for common factors: The expression does not have any common factors that can be factored out. Therefore, the factored form of the expression is: x^5 - 3x^3 + 4x^2 - 12.

I hope this helps! Let me know if you have any further questions.