
Задание: На координатной плоскости изобразите штриховкой решение
неравенств:А)x^2+y^2>16B)y>x^2+72 Задание:На координатной плоскости изобразите штриховкой решение неравенств:А)x^2+y^2<9B)y<x^2-3Срочно помогите прям срочно кто поможет еще 20 баллов в подарок дам

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Ответ:
На 1 задание .




Solution to Inequality A: x^2 + y^2 > 16
To graph the solution to the inequality x^2 + y^2 > 16 on a coordinate plane, we need to shade the region that satisfies the inequality.
First, let's consider the equation x^2 + y^2 = 16. This equation represents a circle with a radius of 4 centered at the origin (0, 0). Since we are dealing with an inequality greater than, the region outside the circle will satisfy the inequality.
To graph the solution, follow these steps: 1. Draw the coordinate axes (x-axis and y-axis). 2. Draw a circle with a radius of 4 centered at the origin (0, 0). 3. Shade the region outside the circle.
The graph should look like this:

Solution to Inequality B: y > x^2 + 72
To graph the solution to the inequality y > x^2 + 72 on a coordinate plane, we need to shade the region that satisfies the inequality.
To graph the solution, follow these steps: 1. Draw the coordinate axes (x-axis and y-axis). 2. Draw a parabola with its vertex at (0, 72) and opening upwards. 3. Shade the region above the parabola.
The graph should look like this:

Solution to Inequality A: x^2 + y^2 < 9
To graph the solution to the inequality x^2 + y^2 < 9 on a coordinate plane, we need to shade the region that satisfies the inequality.
First, let's consider the equation x^2 + y^2 = 9. This equation represents a circle with a radius of 3 centered at the origin (0, 0). Since we are dealing with an inequality less than, the region inside the circle will satisfy the inequality.
To graph the solution, follow these steps: 1. Draw the coordinate axes (x-axis and y-axis). 2. Draw a circle with a radius of 3 centered at the origin (0, 0). 3. Shade the region inside the circle.
The graph should look like this:

Solution to Inequality B: y < x^2 - 3
To graph the solution to the inequality y < x^2 - 3 on a coordinate plane, we need to shade the region that satisfies the inequality.
To graph the solution, follow these steps: 1. Draw the coordinate axes (x-axis and y-axis). 2. Draw a parabola with its vertex at (0, -3) and opening upwards. 3. Shade the region below the parabola.
The graph should look like this:

I hope this helps! Let me know if you have any further questions.


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